Question

A transformer with 1000 turns on its primary coil has an RMS potential difference across this coil of 240V. A voltmeter is connected across the secondary coil and measures 12V. How many turns are on the secondary coil?

Answer 1

Given that the number of turns in the primary coil is

`n_p=\text{ 1000}`

The voltage in the primary coil is

`V_p=240\text{ V}`

The voltage in the secondary coil is

`V_s=\text{ 12 V}`

We have to find the number of turns in the secondary coil.

Let the number of turns in the secondary coil be denoted by

`n_s`

The formula to calculate the number of turns in the secondary coil is

`\begin{gathered} (V_p)/(V_s)=(n_p)/(n_s) \\ n_s=(V_s)/(V_p)* n_p \end{gathered}`

Substituting the values, the number of turns in the secondary coil will be

`\begin{gathered} n_s=(12)/(240)*1000 \\ =50 \end{gathered}`

Thus, the number of turns in the secondary coil is 50