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A transformer with 1000 turns on its primary coil has an RMS potential difference across this coil of 240V. A voltmeter is connected across the secondary coil and measures 12V. How many turns are on the secondary coil?

A transformer with 1000 turns on its primary coil has an RMS potential difference-example-1
User Jaanu
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1 Answer

11 votes
11 votes

Given that the number of turns in the primary coil is


n_p=\text{ 1000}

The voltage in the primary coil is


V_p=240\text{ V}

The voltage in the secondary coil is


V_s=\text{ 12 V}

We have to find the number of turns in the secondary coil.

Let the number of turns in the secondary coil be denoted by


n_s

The formula to calculate the number of turns in the secondary coil is


\begin{gathered} (V_p)/(V_s)=(n_p)/(n_s) \\ n_s=(V_s)/(V_p)* n_p \end{gathered}

Substituting the values, the number of turns in the secondary coil will be


\begin{gathered} n_s=(12)/(240)*1000 \\ =50 \end{gathered}

Thus, the number of turns in the secondary coil is 50

User Anas Karkoukli
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