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A circuit with 0.1 A running through the battery and two 14 Ω resistors in parallel. What is the voltage of the battery?

User Mamba
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1 Answer

8 votes
8 votes

Given that the two resistors are connected in parallel and each resistance is 14 ohms.

The current in the circuit is I = 0.1 A.

We have to find the voltage of the battery.

Let the voltage be denoted by V.

First, we have to find the equivalent resistance.


\begin{gathered} (1)/(R_P)=(1)/(14)+(1)/(14) \\ =(2)/(14) \\ R_p=7\text{ ohm} \end{gathered}

The equivalent resistance is 7 ohm.

According to Ohm's law, the voltage can be calculated by the formula


\begin{gathered} V=R_pI \\ =7*0.1 \\ =0.7\text{ V} \end{gathered}

Thus, the voltage of the battery is 0.7 V.

User WantTheBest
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