Question

Addison studies a tarantula that is 30 mm long suppose she uses a microscope to magnify the spider by 4×10 to the second power how long will the spider appear to be

Answer 1

The magnification factor is given as
`4(10)^2=400`. Therefore multiplying this by the spider's actual length will give its apparent length.
`(400)(30 mm) = 12,000`This gives an apparent length of 12,000 mm.
Since 1,000 mm = 1 m, this apparent length is also equivalent to 12 m.

Answer 2

The microscope magnifies things by 4 * 10 to the second power, which is 4 * 100. It means it magnifies things 400 times.

If the spider's lenght is 30 mm normally, under such microscope he will appear to be 30 * 400 = 12000 mm (which is 1200 cm or 12 m).