Question

!!!!!!!!!!!!150 points!!!!!!!!!! Question bellow.

Answer 1

The answer will be .04
`x^(2)` -0.2xy+0.25
`y^(2)`

using the formula
`a^(2) -2ab + b^(2)`

Answer 2

I thnk you means exand

so
(0.2x-0.5y)^2=(0.2x-0.5y)(0.2x-0.5y)

use distributive prpoety
a(b+c)=ab+ac
so
(0.2x-0.5y)(0.2x-0.5y)=(0.2x-0.5y)(0.2x)+(0.2x-0.5y)(-0.5y)=(0.2x)(0.2x)+(-0.5y)(0.2x)+(0.2x)(-0.5y)+(-0.5y)(-0.5y)=0.4x^2-0.2xy+0.25y^2