Question

Each time mae and ravi play chess, Mae has probability 4/5 of winning. If they play 5 games, determine the probability that:a. Mae wins 3 of the gamesb. Mae winds either 4 or 5 of the games.

Answer 1

a) Probability that Mae wins 3 of the games.

That means Mae wins three games and loose two games, so:

P = (4/5)³ x (1/5)² = 0.02048

b) Mae wins either 4 or 5 of the games.

The probability Mae wins 4 games (win four games and loose one):

P₁ = (4/5)⁴ x (1/5) = 0.08192.

The probability Mae wins 5 games:

P₂ = (4/5)⁵ = 0.32768.

So, the desired probability is

P = P₁+P₂ = 0.08192 + 0.32768 = 0.4096.