Question

find the slope of the line containing the points (-1,6) and (3,5) put final.answer in slope-intercept form

Answer 1

Given the points (-1,6) and (3,5).

The formula to find the slope is

`m=\frac{y_2-y_1_{}}{x_2-x_1}`

Take

`x_1=-1,y_1=6,x_2=3,y_2=5`

Plug the values into the formula and find the slope.

`\begin{gathered} m=(5-6)/(3-(-1)) \\ =(-1)/(4) \end{gathered}`

The slope-intercept form is y = mx+b.

Plug the value of m.

`y=-(1)/(4)x+b`

ThusConsider the point (-1,6). Substitute -1 for x and for y into the equation.

`\begin{gathered} 6=-(1)/(4)(-1)+b \\ =(1)/(4)+b \\ b=6-(1)/(4) \\ =(23)/(4) \end{gathered}`

Thus, the equation of the line in slope intercept form is

`y=-(1)/(4)x+(23)/(4)`