Question

How do you solve m/9 divided by mn squared / 3

Answer 1

`To\ divide\ fraction\ multiply\ first\ fraction\ by\ inverse\ of\ the\ second:\\\\ (m)/(9):(mn^2)/(3)=(m)/(9)*(3)/(mn^2)=(1)/(3n^2) \\\\Solution\ is \ (1)/(3n^2).`

Answer 2

`(m)/(9):(mn^2)/(3) =(m)/(9) \cdot (3)/(mn^2) =(1)/(3n^2)`