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What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?
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Jun 15, 2017
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What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?
Chemistry
high-school
Joginder S Nahil
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Joginder S Nahil
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Molar mass CaCl₂ = 110.98 g/mol
number of moles :
n = m / molar mass
n = 330 / 110.98
n =2,9735 moles
Molarity ( M ) = moles solute / liters solution
M = 2.9735 / 1
M = 2.9735 mol/L⁻¹
hope this helps!
Dredozubov
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Jun 20, 2017
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Dredozubov
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