What is square root of 126 + square root of 56 in standard form

asked Aug 18, 2015 143k views

4 votes

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7 votes

$√(126)+√(56)=√(9*14)+√(4*14)=\sqrt9*√(14)+\sqrt4*√(14)\\\\=3√(14)+2√(14)=5√(14)$

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6 votes

$√(126)= 3√(14) \\ \\ √(56)=2√(14) \\ \\ \\ √(126)+ √(56)= 3√(14)+2√(14)= 5√(14)$

Shane Perry answered Aug 24, 2015

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