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How do I get the volume an density on table 3?Assume tha the given materials have a cylindrical shape

How do I get the volume an density on table 3?Assume tha the given materials have-example-1
User Pspl
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In order to calculate the volume and density of the steel given in the table 3, consider that the shape of the material is a cylinder. Then, the volume is given by:


V=\pi r^2h

where r is the radius of the base and h the height.

In this case, you have:

r = diameter/2 = 1.3 cm/2 = 0.65cm = 0.0065 m

h = 5 cm = 0.05 m

π = 3.14

Replace the previous values into the formula for V and simplify:


V=(3.14)(0.0065m)^2(0.05m)\approx0.0000063m^3

Hence, the volume, in m^3 of the given steel is approximately 0.0000063m^3.

The density is given by:


\text{density}=\frac{\text{mass}}{\text{volume}}

In this case, you have:

mass = 50.7 g = 0.0507 kg

volume = V = 0.0000063m^3


\text{density}=(0.0507kg)/(0.0000063m^3)\approx7639.44(kg)/(m^3)

Hence, the density of the given steel is approximately 7639.44 kg/m^3

User Fxmasa
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