Question

a catcher picks up a baseball from the ground, if the unbalanced force on the ball is 7.25 x 10^-2 N and 4.35 x 10^-2 J of work is done to lift the ball, how far does the catcher lift the ball?

Answer 1

The work is being done against gravity, and equals (Force * vertical distance).
A Joule of work is equivalent to 1 Newton-metre

So vertical distance d = work done / Force
d = 4.35*10^-2J / 7.25*10^-2 N = 0.6 m = 60cm = 600mm