Question

The equation for photon energy, E , isE=hc/λ where h = 6.626×10^−34 J⋅s (Planck's constant) and c = 2.99×10^8 m/s (the speed of light).What is the wavelength, λ , of a photon that has an energy of E = 3.32×10^−19 J ?Express your answer numerically in meters.

Answer 1

The energy for a photon is given by the equation:

`E=(hc)/(\lambda)`

In this case the energy is 3.32e-19 J; plugging this value and solving for the wavelength we have:

`\begin{gathered} 3.32*10^(-19)=((6.626*10^(-34))(2.99*10^8))/(\lambda) \\ \lambda=((6.626*10^(-34))(2.99*10^8))/(3.32*10^(-19)) \\ \lambda=5.97*10^(-7) \end{gathered}`

Therefore, the wavelength is:

`\lambda=5.97\cdot10^(-7)\text{ m}`