Question

Find the distance between the points (-3, 11) and (5, 5).

Answer 1

Formula for distance between two points:

d = √((x₂-x₁)² + (y₂-y₁)²)

Let point 1 be (-3, 11) and point 2 be (5, 5)

Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.

d = √((x₂-x₁)² + (y₂-y₁)²)

= √((5- -3)² + (5-11)²)

= √((5+3)² + (5-11)²)

= √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36

= √(64 + 36)

= √(100)

= 10

Distance = 10 units.

Answer 2

Formula for distance between two points:

d = √((x₂-x₁)² + (y₂-y₁)²)

Let point 1 be (-3, 11) and point 2 be (5, 5)

Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.

d = √((x₂-x₁)² + (y₂-y₁)²)

= √((5- -3)² + (5-11)²)

= √((5+3)² + (5-11)²)

= √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36

= √(64 + 36)

= √(100)

= 10

Distance = 10 units.