Question

Find the product. (3p 4)3 · (p 2)7

Answer 1

Answer:
`3p^(26)`

Explanation:

The given expression:
`(3p^4)^3\cdot(p^2)^7`

According to the law of exponents (Power rule):

`(a^x)^y = a^(xy)`, we get

`=3p^(4*3)\cdot p^(2*7)\\\\= 3p^(12)\cdot p^(14)`

According to the law of exponents (Base rule):

`a^x .\cdot a^y = a^(x+y)`, we get

`3p^(12)\cdot p^(14)=3p^(12 + 14)= 3p^(26)`

Answer 2

3p^26

Explanation:

Given: (3p^4)^3 . (p^2)^7

Using the power of power rule :(a^n)^m = a^mn, we get

3p^(4*3) . p^(2*7)

= 3p^12 . p^14

Using the base rule: a^ m . a^n = a^(m+n), we get [If we have the same base in multiplication, we can add the powers]

= 3p^(12 + 14)

= 3p^26

Answer: 3p^26

Hope this will helpful.

Thank you.