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What two numbers multiply to 15 and add to 6

User RoyB
by
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2 Answers

3 votes
Since there are no number that multiply to 155 and add to 6 you must now use the Quadratic Formula.

x=(-b(+/-)√
b^(2)-4ac)
2a
User JoJo
by
6.4k points
0 votes

Answer:


\left ( (6+√(24)i)/(2)\,,\,(6- √(24)i)/(2) \right )\,,\,\left ((6-√(24)i)/(2)\,,\,(6+ √(24)i)/(2)  \right )

Explanation:

Let a and b be two numbers such that
a+b=6\,,\,ab=15

From equation a + b = 6 , we have b = 6 - a . On putting this value of b in equation ab=15 , we get
a(6-a)=15\Rightarrow 6a-a^2=15\Rightarrow a^2-6a+15=0

We will solve this equation using quadratic formula : For equation of form
Ax^2+Bx+C=0 ,
x=(-B\pm √(B^2-4AC))/(2A)

Solving
a^2-6a+15=0 :


a=(6\pm √(36-60))/(2)=(6\pm √(24)i)/(2)

For
a=(6+√(24)i)/(2) ,
b=6-(6+ √(24)i)/(2)=(12-6-√(24)i)/(2)=(6- √(24)i)/(2)

For
a=(6-√(24)i)/(2) ,
b=6-(6- √(24)i)/(2)=(12-6+√(24)i)/(2)=(6+ √(24)i)/(2)

User Asad Durrani
by
6.5k points
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