Question

Any one know how to find the roots of an equation?

A. 1/4 ± Square root of 10
B. 2/4 ± (i Square root of 10)/4
C. 1 ± (i Square root of 14)/2

i would like to know HOW to solve this problem.

Answer 1

so what you do is
make into ax^2+bx+c=0 form

add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x=
`\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}`

ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x=
`\frac{-(-2)+/- \sqrt{(-2)^(2)-4(1)(9/2)} }{2(1)}`
x=
`(2+/- √(4-(36/2)) )/(2)`
x=
`(2+/- √(4-(18)) )/(2)`
x=
`(2+/- √(-14) )/(2)`
x=
`(2+/- √(-14) )/(2)`
x=
`1+/- (√(-14) )/(2)`
x=
`1+/- (√(14) √(-1))/(2)`
x=
`1+/- (√(14) i )/(2)`
x=
`1+/- ( i √(14) )/(2)`

answer is C