Question

Would just like to make sure that my answer is correct.Answer 5 only please

Answer 1

Given:

`\tan \theta=(1)/(7)`

Opposite side= 1 ; adjacent side=7

`\begin{gathered} \text{hypotenuse}=\sqrt[]{1^2+7^2} \\ \text{hypotenuse}=\sqrt[]{1^{}+49^{}} \\ \text{hypotenuse}=\sqrt[]{50^{}} \\ \text{hypotenuse}=5\sqrt[]{2} \end{gathered}`
`\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{hypotenuse\text{ side}}=\frac{1}{5\sqrt[]{2}} \\ \cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse side}}=\frac{7}{5\sqrt[]{2}} \\ co\sec \theta=\frac{5\sqrt[]{2}}{1}=5\sqrt[]{2} \\ \sec \theta=\frac{5\sqrt[]{2}}{7} \\ \cot \theta=(7)/(1)=7 \end{gathered}`