A football is kickedat 23.4 m/s at a38.5° angle. How faraway does it land?(Unit = m)3:11 PM5/12/2621

510,546 views

11 votes

2.6k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

11 votes

The horizontal distance travelled by the football is,

$R=(u^2\sin(2\emptyset))/(g)$

Substituting the known values,

$\begin{gathered} R=((23.4)^2\sin(2*38.5))/(9.8) \\ R=54.44\text{ m} \end{gathered}$

Thus, the horizontal distance travelled by the football is 54.44 m.

Andnik answered Feb 2, 2023

2.5k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers