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Please find all values of "a" such that ax^2+3x+5=0 has two real roots.

User Roman Yakoviv
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1 Answer

13 votes
13 votes

The general form of a quadratic equation is expressed as

ax^2 + bx + c

The given quadratic equation is expressed as

ax^2+3x+5=0

By comparing both equations,

a = a

b = 3

c = 5

The discriminant of a quadratic equation is expressed as b^2 - 4ac

If b^2 - 4ac > 0, then the equation has 2 real roots

by substituting the above values into the discriminant, it becomes

3^2 - 4 * a * 5 > 0

9 - 20a > 0

9 > 20a

20a < 9

a < 9/20

a < 0.45

The values of a for which the equation would have 2 roots would be a < 0.45f

3ions,

a = a

b = 3

c = 5t

User Mike Hewitt
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3.1k points