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Perform the indicated operation.

(4g 2 - 9) ÷ (2g - 3)
2g - 3
2g + 3
2g + 3 R 18

User Ludivine
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1 Answer

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(4g^2 - 9) --> this can be factored out.
After factorization, you will get --> (2g-3)(2g+3)

Divide the whole factor by (2g-3)
[ (2g-3)(2g+3) ] / (2g-3)
The final answer is 2g + 3.
User BrumScouse
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