Question

The principal root of the square root of 18 would fall between what two integers?

Answer 1

Now, 18 is not a perfect square, because its square root is a recurring decimal

`\sqrt[]{18}=4.2426406\ldots.`

18 lies between two perfect squares, which are 16 and 25

`\begin{gathered} \sqrt[]{16}=4 \\ \sqrt[]{25}=5 \end{gathered}`

So the squre root of 18 will be greater than 4, but less than 5.

That is 4 is less than the square root of 18, and square root of 18 is less than 5. Which is

`4<\sqrt[]{18}<5`

Option A is the correct answer