Answer:
2.58 * 10^19 atoms of titanium
Step-by-step explanation:
Mass of Titanium ions deposited = 2.05 * 10^-3 g of Ti
Molar mass of titanium = 47.87 g/mol
Number of moles of Titanium deposited = 2.05 * 10^-3 g/47.87 g/mol = 4.28 * 10^-5 moles
Number of atoms of titanium deposited = number of moles of titanium * Avogadro's number
Number of atoms of titanium deposited =4.28 * 10^-5 moles * 6.02 * 10^23 = 2.58 * 10^19 atoms of titanium