Question

Given the point and slope write the equation of the line (9, -4); slope = -2/3

Answer 1

Given the point and the slope of the line:

Slope = -2/3

Point = ( 9 , -4 )

the general equation of the line in slope - intercept form is ;

`y=m\cdot x+b`

Where : m is the slope and b is y - intercept

m = -2/3

so, the equation will be:

`y=(-2)/(3)x+b`

We will find b using the point ( 9 , -4)

When x = 9 , y = -4

so,

`\begin{gathered} -4=(-2)/(3)\cdot9+b \\ \\ -4=-6+b \\ b=-4+6=2 \end{gathered}`

So, the equation of the line is:

`y=(-2)/(3)x+2`