Question

Solve 3x^2+2x-8=0, using an algebraic method.

Answer 1

you should factor this question so you will have:
(3x - 4)(x +2)
so now you have:
(3x-4)(x+2)=0 ⇒ 3x -4 =0 and x+2 =0
3x-4=0 ⇒ 3x = 4 ⇒ x = 4/3 and
x + 2 =0 ⇒ x = -2 :)))
so you have two x
x = -2, 4/3 :)))
i hope this is helpful
have a nice day