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How much force is exerted on a 60 kg person who hits an airbag at 45 m/s if the impact takes 0.65 seconds? Please give me an explanation as to how you got the answer if you can :)

User Lagistos
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1 Answer

6 votes
We must rewrite the Newton's Second Law:


F_(av)=ma_(av)~~~~

Applying in the question:


F=60( (45)/(0.65) ) \\ \boxed {F \approx 4.15~kN}