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How many L of a .05 M HCL solution can be made by diluting 250 ml of 10 M HCL
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How many L of a .05 M HCL solution can be made by diluting 250 ml of 10 M HCL

User Dharga
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1 Answer

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Mi * Vi = Mf * Vf

10 * 0.25 = 0.05 * Vf

2.5 = 0.05* Vf

Vf = 2.5 / 0.05

Vf = 50 L

hope this helps!



User Ninetiger
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