Question

How many liters of 4 M solution can be made using 100 grams of lithium bromide?

Answer 1

Molar mass of LiBr ( lithium bromide ) = 86.845 g/mol

Amount of calculation to moles of lithium bromide (LiBr)

86.845 g ------------- 1 mole
100 g ----------------- ?

n = m / M

n = 100 / 86.845

n = 1.1514 moles of LiBr

V ---------------------1.1514 moles
1 L -------------------- 4 M

1.1514 * 1 / 4

V = 1151.4 / 4

V = 0,28785 L

hope this helps!

hope this helps !