2.
volume of a pyramid = 1/3* B * h
B = base area = area of a square = side lenght ^2=16^2
heigth = h
To find height apply the Pythagorean theorem
c^2 = a^2+b^2
10^2 = 8^2+ h^2
100 = 64+h^2
100-64 = h^2
36 =h^2
√36 = h
h=6
V = 1/3 * 16^2*6 = 512 units 3
Surface Area = B + 1/2 p s
p = perimeter of the base = 16x4 = 64
s = slant heigth = 10
SA = 16^2+ 1/2 (64)10 = 256+ 320= 576 units2
Lateral Area = LA
LA = 1/2 Ps = 1/2 (64) 10 = 320