Question

Friday can what is the greatest parameter of a rectangle with an area of 39 ft.²

Answer 1

The area is 39*1=39, and the perimeter would be 39+39+1+1=80.

Answer 2

the greatest perimiter
let's experiment weather we want to have sides with as close to each other as possible, or with as far apart form each other

so if we have lenth times width, peimiter=legnth+legnth+widht+width

1 times 39:perimiter=80
3 times 13:perimiter=52


so we want one side as small as possible
0.1 times 360:perimiter=720.2

let's see how far we can go
0.00000000000000000001 times 3600000000000000000000=3,600,000,000,000,000,000,000.00000000000000000001

you get the idea
that is a really big perimiter
if you can be that exact

so just make a really small decimal

if you haven't learned decimals yet and only know whole numbers then
80 ft is the greatest perimiter made (with sides of 39,1,39,1)