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Solve expression using PEMDAS and Distribution
3 (x+5)

User Starvator
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\huge\textbf{Hey there!}


\huge\text{Formula for distributive property}


\large\textbf{a(b + c)}


\large\textbf{= a(b) + a(c)}


\large\textbf{= ab + ac}


\huge\textsf{Now, we can answer your question}


\large\textbf{3(x + 5)}


\huge\textsf{DISTRIBUTE 3 WITHIN the PARENTHESES}


\large\textbf{= 3(x) + 3(5)}


\huge\textsf{SIMPLIFY IT!}


\large\textbf{= 3x + 5}


\huge\textsf{Therefore, your answer is: \boxed{\mathsf{3x + 15}}\huge\checkmark}


\huge\textbf{Good luck on your assignment \& enjoy}\\\huge\textbf{your day!}

~
\frak{Amphitrite1040:)}

User Blade
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4 votes
PEMDAS stand for Parentheses, Exponent, Multiplication, Division, Addition, and Subtraction.

3(x+5)

In this expression, we cannot perform any operation within the parentheses so we move to the next operation in the expression which is multiplication.

3(x+5)
becomes:
3x + 3(5)
3x + 15

We need to look for the value of x.

3x + 15 = 0
3x = -15
3x/3 = -15/3
x = -5

We need to substitute x by its value.

3(x + 5)
3(-5 + 5)

we can perform the P in PEMDAS
3(0) = 0

multiply.
3(0) = 0
0 = 0

Rule of zero. any number multiplied by zero is equal to zero.
User Alan Shiah
by
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