Question

Solve using quadratic formula

`2k {}^(2) - 3 = 0`
​

Answer 1

`\bold{k=\pm(\sqrt6)/(2)\approx\pm1.22}`

Explanation:

`2k^2-3=0\\\\a=2\,,\ \ b=0\,,\ \ c=-3\\\\k=(-0\pm√(0^2-4\cdot2\cdot(-3)))/(2\cdot2)=(\pm√(24))/(2\cdot2)=(\pm2√(6))/(2\cdot2)=\pm(\sqrt6)/(2)\approx\pm1.22`