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The perimeter of a rectangle is 160 feet. If the length of the rectangle is 28 feet more than the width, what are the dimensions of the rectangle?

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Answer:

width = 26 ft

length = 54 ft

Explanation:

perimeter = 160 ft

width = x

length = x + 28

Perimeter = 2(width) + 2(length)


2x + 2(x + 28) = 160 \\ 2x + 2x + 56 = 16 0\\ 4x = 160 - 56 \\ x = (104)/(4) \\ x = 26

width = x = 26

length = x + 28 = 26 + 28 = 54

User Marie Dm
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