Question

Which point lies on the graph of the boundary line of the inequality 3y + 4x < 12?

Answer 1

`3 y + 4 x \ \textless \ 12`

Subtract 4 x from both sides


`3y+4x-4x \ \textless \ 12-4x`
`3y\ \textless \ 12 - 4x`

Divide both sides by 3 :


`(3y)/(3) \ \textless \ (12-4x)/(3)`


`y\ \textless \ (12-4x)/(3)`


Image attached

hope this helps!