Question

∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'. If vertex A is at (-1, 2) and vertex B is at (1, 5), then vertex A' is at

Answer 1

Answer: (-4,8)

Explanation:

The translation rule for translating a point h units left is given by :-

`(x,y)\to (x-h,k)`

The translation rule for translating a point k units up is given by :-

`(x,y)\to (x,y+k)`

Given : ∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'. If vertex A is at (-1, 2) and vertex B is at (1, 5).

Then, the vertex A' will be :-

`A(-1,2)\to(-1-3,\ 2+6)=(-4,\ 8)`

Hence, the vertex A' is at (-4,8).

Answer 2

So we want to know the new coordinates for the vertex A'(x,y) if we know that the vertex A is at A(-1,2) and vertex B is at B(1,5) and that the triangle ABC is translated 6 units up and 3 units left. So the method is simply to add units 6 to x and 3 to y of A to get A'. Going left means we need to go to negative x direction and going up means we need to go to positive y direction. So: A'(-1-3,2+6) and that is: A'(-4,8).