Question

Point a (2,2) translates with the rule (x+3, y+4) to point

b. what is the diagonal distance of the translation from point a to point b?

Answer 1

`\displaystyle \bf\\ A(2,~2)\\ B(x+3,~y+4) \Longrightarrow B(2+3,~2+4)\Longrightarrow B(5,~6)\\ \texttt{distance }~~AB = \sqrt{\bf \Big(x_(_B)-x_(_A)\Big)^2+\Big(y_(_B)-y_(_A)\Big)^2} = \\\\ =√(\bf \Big(5-2\Big)^2+\Big(6-2\Big)^2) = √(\bf 3^2 + 4^2)=√(\bf 9 + 16)= √(\bf 25) = \boxed{\bf 5~units }`