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A car travels at a constant speed around a circular track whose radius is 2.9 km. the car goes once around the track in 400 s. what is the magnitude of the centripetal accelerat…
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A car travels at a constant speed around a circular track whose radius is 2.9 km. the car goes once around the track in 400 s. what is the magnitude of the centripetal accelerat…
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Jan 1, 2018
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A car travels at a constant speed around a circular track whose radius is 2.9 km. the car goes once around the track in 400 s. what is the magnitude of the centripetal acceleration of the car?
Mathematics
high-school
Jarrell
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Jarrell
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First we need the linear velocity
D=2*Pi*r=2*pi* 2.9=18.22 km=18,221.23m
V=D/T=18,221.23m/400s=
45.55
m/s
A=V^2/r=(45.55 m/s)^2/2900m=
0.72
m/s^2
the magnitude of the centripetal acceleration of the car is 0.72 m/s^2
Bill Dudney
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Jan 7, 2018
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Bill Dudney
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