If k is constant, what is the value of k that hte polynomial k^2x^3-6kx 9 is divisible by x-1

asked Jan 19, 2018 198k views

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Solve k²-6k+9=(k-3)²=0, so k=3. The polynomial becomes 9x³-18x+9=9(x³-2x+1)=9(x-1)(x²+x-1).

Seren answered Jan 23, 2018

by Seren

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