Answer:
.7147
Explanation:
Let P be the probability of 55 families having mean more than 17
P { (17-17.2)/ (2.5/√55) }
P(- 0.5933 )
= - .2765 [ From the z table ]
P be the probability of 55 families having mean less than 18
P { (18 -17.2)/ (2.5/√55) }
P( 2.3732 )
= .9912 [ From the z table ]
Probability of mean between 17 and 18
= .9912 - .2765
= .7147