Compound A : SnCl2
the mass ratio of Cl and Sn: 71 g Cl/ 119 g Sn = 0.579 g Cl/ 1 g Sn
Compound B: the ratio of mass of chlorine per 1 g Sn is twice the ratio of chlorine per 1 g Sn in compound A => 1,194 g Cl/ 1 g Sn = 142,086 g Cl/ 119 g Sn
=> the number of chlorine/ 1 atom Sn = 142.086/ 35.5 = 4.
=> the formula of B: SnCl4