91.1k views
1 vote
What is the density of a mineral with a mass of 41.2 g and a volume 8.2 cm3?

2 Answers

3 votes
hey there!:

mass = 41.2 g

Volume = 8.2 cm³

Therefore:

D = m / V

D = 41.2 / 8.2

D = 5.02 g/cm³
User Mtkilic
by
8.3k points
5 votes

Answer : The density of a mineral is, 5.024 g/ml

Solution : Given,

Mass of mineral = 41.2 g

Volume of mineral =
8.2cm^3=8.2ml
(1cm^3=1ml)

Formula used :


Density=(Mass)/(Volume)

Now put all the given values in this formula, we get the density of mineral.


Density=(41.2g)/(8.2ml)=5.02g/ml

Therefore, the density of a mineral is, 5.024 g/ml

User Rolly
by
8.6k points

No related questions found