Question

[xe] 6s2 is the noble gas configuration for which element

Answer 1

Answer : The element is, Barium.

Explanation :

Noble gas : It is the tendency of a chemical elements to gain or lose electrons to reach the electronic configuration of the noble gas.

As we know that if the element belongs to s-block , its group number = Number of valence electrons (or outermost shell electrons).

Period number = The number present before the outermost shell of an element

The given noble gas electronic configuration is,
`[Xe]6s^2`

Form the electronic configuration we conclude that, the period number is, 6 and the group number is, 2 (because there are 2 valence electrons in outermost shell).

Thus, the element is barium that belongs to group 2 and period 6.

Answer 2

We are tasked to find the element which has a noble gas electronic configuration [Xe] 6s2. First tasked is to find the molecular number and add 2 as the last orbital electron. Thus, we have an element that has a molecular number of 54+2= 56. Looking on the periodic table, find an element that has 56 as the molecular number. That element is Barium (Ba).