Question

A piano emits frequencies that range from a low of about 28 hertz to a high of about 4200 hz.find the range of wavelength in air attained by this instrument when the speed of sound in air in 342m /s

Answer 1

The solution for this problem is:
A velocity of wave is given as V = λ⋅f
V - velocity of wave
f - frequency of wave
λ - wave length

So getting the wave length is:
λ = V/f
λminimum = V / fmaximum
λminimum = 342 / 4200
λminimum = 0.081 m

λmaximum = V/ fminimum
λmaximum = 342 / 28
λmaximum = 12.214 m