Question

A cheetah is walking at 1.0 m/s when it sees a zebra 25 m away. what acceleration would be required to reach 20.0 m/s in that distance?

Answer 1

Let
a = acceleration.
v = Speed
r = position
t = time.
To find the answer, you must write the equations of speed, and position known and clear the variables that are needed to find the acceleration.
The answer is a = 7.98m / s ^ 2.
I attach the solution.