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QUESTION 1
Find the remaining sides of a 30° -60°-90° triangle if the shortest side is 3.

User Andrex
by
4.3k points

2 Answers

6 votes

Answer:

the other sides are 6 and 3√3

Explanation:

User Niyati
by
4.1k points
12 votes

Answer:

x = 6

Explanation:

Right Triangle

We are given a right triangle whose shortest side has a length of 3 units. This side must be opposite to the smallest acute angle of 30°.

The triangle is shown in the figure attached.

The tangent ratio relates the opposite side with the adjacent side. The formula can be applied to the angle of 30° as follows:


\displaystyle \tan 30^\circ=\frac{\text{opposite leg}}{\text{adjacent leg}}


\displaystyle \tan 30^\circ=(3)/(y)

Solving for y:


\displaystyle y=(3)/(\tan 30^\circ)

Since:


\tan 30^\circ=(1)/(√(3))


\displaystyle y=3√(3)

Now applying the sine to find the hypotenuse x:


\displaystyle \sin 30^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}


\displaystyle \sin 30^\circ=(3)/(x)

Solving for x:


\displaystyle x=(3)/(\sin 30^\circ)

Since:


\sin 30^\circ=(1)/(2)


\displaystyle x=(3)/((1)/(2))

x = 6

QUESTION 1 Find the remaining sides of a 30° -60°-90° triangle if the shortest side-example-1
User Martincho
by
4.2k points