Log (x+6=log (x-3)+log 2

asked Jul 27, 2018 9.7k views

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$log(x + 6) = log(x - 3) + log(2) \\ = > log(x + 6) = log(x - 3) (2) \\ = > x + 6 = 2x - 6 \\ = > x - 2x = - 6 - 6 \\ = > - x = - 12 \\ = > x = 12$

x = 12

Sgrove answered Jul 30, 2018

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Log(x+6) = log(x-3) + log(2).

(X+6) = 2 (x-3)

X+6 = 2x - 6

6 = x-6

X = 12

Lukr answered Aug 3, 2018

by Lukr

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