Question

The equation of motion is given by s(t) = 6t2 + t + 8 at 1:05 P.M. What is the average velocity from 1:07 P.M. to 1:09 P.M. in meters/second?

Answer 1

The answer would be: 37m/s

Assuming that the unit t used is minutes after 1.:05,
when the time is 1:07 P.M. the value of t would be: 1:07 - 1:05= 2
s(2)= 6(2)^2 + (2) + 8 = 34
when the time is 1:09 P.M. the value of t would be: 1:09 - 1:05= 4
s(4) = 6(4)^2 + (4) + 8= 108

Then, the function for average velocity would be:
average velocity= total distance/time
s(4)-s(2)/4-2=
(108- 34) /2=
74/2= 37m/s