176k views
0 votes
The Plainview Middle School basketball team has 8

players. If a player can play any position, in how many ways can 5 starting players be selected?

User JazzMaster
by
8.9k points

2 Answers

5 votes
Probability is easier than talked through or with pictures
denominator 8 positions
8
lose one position (2nd player)
X 7
lose one position (3rd)
X 6
lose one position (4th)
X 5
lose one position (5th)
X 4

8 x 7 x 6 x 5 x 4 = 6720 combinations
User Adrian Iftode
by
8.4k points
4 votes
To solve a probability, you need to determine if the order is important or not. The word "If a player can play any position," indicates that the team doesn't need to specify the order. So, the possible way to pick a team of 5 players out of 8 people would be:
8C5= 8!/ 5!(8-5)!=
8C5= 8*7*6/ 3*2=56 ways
User Alex Keil
by
8.5k points

Related questions

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories