Question

find the equation of a straight line passing through the points (3,2)and (-3,6)giving the answer in the form x/a+y/b ,where a and b are constants

Answer 1

slope of line =
`(6-2)/(-3-3)= (4)/(-6) =- (2)/(3)`

the equation :
`(y-2)= (-2)/(3)(x-3)`

3y - 6 = -2x + 6, 2x+3y =12 (you can divide by 12 to get the equation straight away)

to get the intercept of both the x-axis and y-axis:

the intercept of x-axis (y=0) , 2x=12 , x = 6

the intercept of y-axis (x=0) , 3y=12 , y = 4

the equation is :
`(x)/(6) + (y)/(4) =1`