Question

What is the equation of the vertical asymptote of g(x)=4 log 3 (x−2)+5 ?

Answer 1

That would be when x = 2 which will make it log3 = 0

Answer x = 2

Answer 2

x = 2

Explanation:

Assuming the function is

`g(x) = 4 \log_(3) (x - 2) + 5`

All logarithmic functions, despite their base, has a vertical asymptote at argument = 0.

That is not changed by the vertical stretching made by the 4 which multiplies the logarithm nor the vertical shift made by the +5.

In this case the argument is x - 2, then the vertical asymptote is:

x - 2 = 0

x = 2